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interpret instruction keywords as names within expressions

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Marc Zinnschlag 2014-02-12 09:56:25 +01:00
parent c0a6acfe6c
commit 93d4743012
1 changed files with 11 additions and 0 deletions
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11
components/compiler/exprparser.cpp
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@ -344,6 +344,17 @@ namespace Compiler
bool ExprParser::parseKeyword (int keyword, const TokenLoc& loc, Scanner& scanner) bool ExprParser::parseKeyword (int keyword, const TokenLoc& loc, Scanner& scanner)
{ {
if (const Extensions *extensions = getContext().getExtensions())
{
std::string argumentType; // ignored
bool hasExplicit = false; // ignored
if (extensions->isInstruction (keyword, argumentType, hasExplicit))
{
// pretend this is not a keyword
return parseName (loc.mLiteral, loc, scanner);
}
}
mFirst = false; mFirst = false;
if (!mExplicit.empty()) if (!mExplicit.empty())